Sunday 20 January 2019

Vedic Mathematics

Vedic Mathematics
(https://ramamohanraocheruku.blogspot.com/2019/01/vedic-mathematics.html)


Vedic Mathematics
Subtraction

08\02\19

At the outset let us formulate the facts we know and require in a sequential order for our use take complement numbers to the base 10. That is 1-9, 2-8, 3-7, 4-6, 5-5. This is the first requisite to be remembered. This we call as base complement.
Now we come to subtractions.
Here let us consider one simple example.
987
654
-----
333
-----
This does not require any effort. Any method will work out.
Now take this example.
                                     753                                    
578
-----
175
-----
{(10+3)-8=5} in the units place; {(10+4)-7=7} in 10s place and {(6-5) =1} in the 100s place is the answer. i.e. 175.
Let us now do it by Vedic Way.
Here we adopt solving the problem from right to left.
753
578
-----
175
-----
{(7-5) = 2}; but in 10s place 7 can’t be subtracted from 5;
Hence cut 1 from {(7-5) = 2} i.e. we get 1. Keep it in 100s place of the answer. In 10s place we have 5 and 7. If 10 is the base, the complement of 7  is 3 and add it to the upper digit 5. You get 8. But the number 8 in unit’s place is bigger than 3 which is above it. Hence reduce 1 from 8, you get 7 and keep that in the 10s place of the answer. Now take the complement of 8 i.e. 2 and add it to its upper number i.e. 3; you get 5 and keep it in the units place of the answer. So we get the answer as 175. A little practice make you perfect to get the answer in seconds.
This method is hassle free as it does not require borrowing 10 adding it to upper number and then subtracting.

Doubling Any Number

Square of any number consisting only 9s by Vedic Way
                    ---------------------------- *****------------------------------------  
23\01\19    

(99)2 = 9801
For any number containing only 9 repeated in it has the simplest way of finding the product very easily by Vedic way. Of the two 9s available keep one 9 as it is and the next 9 split as 8 and 1 leaving one space in between. That is write it as 98 1. Now in the space available keep as many zeros as the number of 9s the said number contains. I mean write it as 9801. That’s all it is the answer.
Another example: (999)2= 998  1 (2 spaces in between 8 and as there are 2 ‘9’s.). Now keep 2 zeros.
So (999)2= 998001. That’s all.
(9999)= 99980001.

(99999)2 = 9999800001 and so on.

Today I would like to introduce to you the method of doubling any number in the Vedic way.To take the method to your heart I would like to introduce 0 to 9 in a typical way. Let us make the single set into 2 sets like the way that follows.
01234 and 56789. The difference between these two sets is the first digit when doubled either by adding the same number or by multiplication by 2 we get only a single digit as answer. Where as in the second set we get a double digit with 1 in the 10's place. With this small concept in mind we take off to double any number.
Initially we start with a 2 digit number.
'Ankanam vamathogathih' is the Vedic Rule i.e. counting is to be reckoned from left to right.
Example:
43 +43 or 43x2 you know both are same.
So from left multiply 4 by 2. It is 8 and 3 also by 2. It is 6. Hence the answer is 86.
Let us take up 93. 9x2=18 and 3x2=6. Therefore answer is 186.
Let us take 79. 7x2=14 but 9x2=18 (As 9 falls in the second set and as it gets 1 in the 10's place add that 1 to 4 contained in 14. Therefore it becomes 15. We are only left with 8 now. Write it simply in the units place. The answer is 158.
Apply the same method for a bigger number also.
Ex. 75386x2= (Left to right) (14+1)0(6+1) (6+1)2 = 150772 is the answer.

Hope you have followed. Write in the comment box only on this issue if you have any doubt. Any other doubt not pertaining to this will not be answered.

Vedic way of squaring 2 digit numbers


Today I would like to present as to how Vedic Mathematical application be made in the case of squaring any two digits
(23)2
First multiply all the digits i.e. 2x3x2 (I have multiplied 2 and 3 along with the 2 available in the square outside the bracket
We get 2x3x2=12
Now square the 2 of the number 23, and the next 3 of 23. Write the answer in two places, I mean
Like: 0409.
Now add the product 12 we got above to the number 0409 leaving the units place
i.e. 0409
        12
      ------
      0529
As 0 has no value the answer is 529. You can check it with usual method.

2. Now take (89)2 =
8x9x2= 144
6481
144
------- 
7921
------   
Just understand how great our ancestors are!

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